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How to implement a listener

I have a design issue. I need to implement a listener. I saw the following SO question: How to create our own Listener interface in android?

But in the link it provides in the answer, author creates a listener which just extends the system-defined listener. E.g onClick, you would do some validation & then call another method called "whenValidatedListener"

I need to define listeners which are not linked to existing event listeners. Basically there would be some processing going on in native(C/C++) code & in the Android code I need a listener to respond to certain messages from it.

I think I could do this using handlers. But AsyncTask is the recommended approach for multithreading.

Is there a way to implement a user-defined-listener using AsyncTask?

like image 786
OceanBlue Avatar asked May 09 '11 20:05

OceanBlue


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2 Answers

AsyncTask has nothing to do with implementing a listener.

Here's a listener:

public interface TheListener {
    public void somethingHappened();
}

Call it however you want. For example, here's a class doing something like View:

public class Something {
    private TheListener mTheListener;

    public void setTheListener(TheListener listen) {
        mTheListener = listen;
    }

    private void reportSomethingChanged() {
        if (mTheListener != null) {
            mTheListener.somethingHappened();
        }
    }
}

You can make this as complicated as you want. For example, instead of a single listener pointer you could have an ArrayList to allow multiple listeners to be registered.

Calling this from native code also has nothing to do with implementing a listener interface. You just need to learn about JNI to learn how native code can interact with Java language code.

like image 57
hackbod Avatar answered Sep 19 '22 05:09

hackbod


Just to clear things up;

you do exactly what @hackbod said and add this :

the activity which encloses the class (with the method setListener(Listener listen)), implements Listener and in it's oncreate or onResume or where-ever you call yourClass.setListener(this).

like image 43
MacD Avatar answered Sep 23 '22 05:09

MacD