How to ignore newline in regexp in Javascript ?
for example:
data = "\
<test>11\n
1</test>\n\
#EXTM3U\n\
"
var reg = new RegExp( "\<" + "test" + "\>(.*?)\<\/" + "test" + "\>" )
var match = data.match(reg)
console.log(match[1])
result: undefined
In pattern matching, the symbols “^” and “$” match the beginning and end of the full file, not the beginning and end of a line. If you want to indicate a line break when you construct your RegEx, use the sequence “\r\n”.
Regex recognizes common escape sequences such as \n for newline, \t for tab, \r for carriage-return, \nnn for a up to 3-digit octal number, \xhh for a two-digit hex code, \uhhhh for a 4-digit Unicode, \uhhhhhhhh for a 8-digit Unicode.
Use the String. replace() method to remove all line breaks from a string, e.g. str. replace(/[\r\n]/gm, ''); . The replace() method will remove all line breaks from the string by replacing them with an empty string.
By default in most regex engines, . doesn't match newline characters, so the matching stops at the end of each logical line. If you want . to match really everything, including newlines, you need to enable "dot-matches-all" mode in your regex engine of choice (for example, add re. DOTALL flag in Python, or /s in PCRE.
In JavaScript, there is no flag to tell to RegExp()
that .
should match newlines. So, you need to use a workaround e.g. [\s\S]
.
Your RegExp would then look like this:
var reg = new RegExp( "\<" + "test" + "\>([\s\S]*?)\<\/" + "test" + "\>" );
You are missing a JS newline character \
at the end of line 2.
Also, change regexp to:
var data = "\
<test>11\n\
1</test>\n\
#EXTM3U\n\
";
var reg = new RegExp(/<test>(.|\s)*<\/test>/);
var match = data.match(reg);
console.log(match[0]);
http://jsfiddle.net/samliew/DPc2E/
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