How to ignore hidden files in fs.readdir result

Question

In node application i need to get all the files in the directory except that hidden files. I have tried fs.readdir but it displaying hidden files also.

Answer 1

Using the regex from this answer, this simple solution removes all hidden files from the result:

fs.readdir('/path/to/directory', (err, list) => {   list = list.filter(item => !(/(^|\/)\.[^\/\.]/g).test(item));    // Your code }); 

Answer 2

You can use:

fs.readdir('/path/to/directory', function(err, list) {   list.forEach(function (filename) {     if(! /^\..*/.test(filename)) {       // display files     }   }); });