My code contains a vertical box layout which is a combination of a vertical box layout in left and one at right. I was wondering if there is a way to hide the left layout with all its widgets when a certain signal is emitted.
You could cheat and use a frame instead of a layout: It works exactly the same way, except for the fact you have to set a layout on the frame for it to work properly. You can then do the following:
from PyQt5 import QtWidgets
# create the frame object.
frame = QtWidgets.QFrame()
# you can do this with any layout - vbox, grid, hbox...
# There will not be more than one item in it anyway.
ly = QtWidgets.QVBoxLayout()
frame.setLayout(ly)
# we're assuming here that parent_layout is some outside layout object.
parent_layout.addWidget(frame)
# hide the frame and its contents
frame.hide()
# show the frame and its contents
frame.show()
I was looking for a solution like this, hope this helps :)
You can't hide a layout, but you can hide a widget.
So first put all the widgets in a container widget. Then connect your signal to the setHidden()
slot of the container widget. Your signal should emit True
or False
, depending on whether you want to hide or show the widgets. Alternatively, you could connect your signal to a simple toggle slot, like this:
def toggleLeftWidget(self):
self.leftWidget.setHidden(not self.leftWidget.isHidden())
In which case, it wouldn't matter what your signal emitted.
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