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How to handle floats and doubles when implementing -hash in objective-c

I'm a newbie at Objective-C and I'm looking for the best way to handle primitive floats and double when implementing the -hash method in an Objective-C class. I've found some good advise on isEqual and hash in general in this question:

Best practices for overriding isEqual: and hash

but it doesn't say anything on how to deal with floats and doubles.

My best attempt:

...
long lat = [[NSNumber numberWithDouble:self.latitude] longValue];
result = prime * result + (int) (lat ^ (lat >>> 32));
...

but I'm not sure this is the correct way. Any ideas ?

like image 240
Age Mooij Avatar asked Mar 04 '11 14:03

Age Mooij


2 Answers

Advice of @JeremyP about using NSNumber was pretty good, but I followed this more into depth. Since CoreFoundation is open source, I found how does CFNumber implement hashing function and this is what I found:

Split the number to integral and fraction part, hash both parts and sum them. Integral part is hashed by modulo and a hash-factor, fraction part is hashed only by multiplication.

NSUInteger HashDouble(double value) {
    double absolute = ABS(value);
    double integral = round(absolute);
    double fragment = absolute - integral;
    NSUInteger integralHash = 2654435761U * fmod(integral, NSUIntegerMax);
    NSUInteger fragmentHash = fragment * NSUIntegerMax;
    return integralHash + fragmentHash;
}

Original source code from CoreFoundation wth comments:

/* For use by NSNumber and CFNumber.
  Hashing algorithm for CFNumber:
  M = Max CFHashCode (assumed to be unsigned)
  For positive integral values: (N * HASHFACTOR) mod M
  For negative integral values: ((-N) * HASHFACTOR) mod M
  For floating point numbers that are not integral: hash(integral part) + hash(float part * M)
  HASHFACTOR is 2654435761, from Knuth's multiplicative method
*/
#define HASHFACTOR 2654435761U

CF_INLINE CFHashCode _CFHashInt(long i) {
    return ((i > 0) ? (CFHashCode)(i) : (CFHashCode)(-i)) * HASHFACTOR;
}

CF_INLINE CFHashCode _CFHashDouble(double d) {
    double dInt;
    if (d < 0) d = -d;
    dInt = floor(d+0.5);
    CFHashCode integralHash = HASHFACTOR * (CFHashCode)fmod(dInt, (double)ULONG_MAX);
    return (CFHashCode)(integralHash + (CFHashCode)((d - dInt) * ULONG_MAX));
}

From file ForFoundationOnly.h on opensource.apple.com.

like image 171
Tricertops Avatar answered Oct 21 '22 15:10

Tricertops


On the assumption that Apple's implementation of -hash is adequate, what is wrong with

result = [[NSNumber numberWithDouble: [self latitude]] hash];

Or using the modern syntax

result = [@([self latitude]) hash];
like image 41
JeremyP Avatar answered Oct 21 '22 14:10

JeremyP