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How to grep download speed from wget output?

I need to download several files with wget and measure download speed.

e.g. I download with

wget -O /dev/null http://ftp.bit.nl/pub/OpenBSD/4.7/i386/floppy47.fs http://ftp.bit.nl/pub/OpenBSD/4.7/i386/floppyB47.fs

and the output is

--2010-10-11 18:56:00--  http://ftp.bit.nl/pub/OpenBSD/4.7/i386/floppy47.fs
Resolving ftp.bit.nl... 213.136.12.213, 2001:7b8:3:37:20e:cff:fe4d:69ac
Connecting to ftp.bit.nl|213.136.12.213|:80... connected.
HTTP request sent, awaiting response... 200 OK
Length: 1474560 (1.4M) [text/plain]
Saving to: `/dev/null'

100%[==============================================================>] 1,474,560    481K/s   in 3.0s

2010-10-11 18:56:03 (481 KB/s) - `/dev/null' saved [1474560/1474560]

--2010-10-11 18:56:03--  http://ftp.bit.nl/pub/OpenBSD/4.7/i386/floppyB47.fs
Reusing existing connection to ftp.bit.nl:80.
HTTP request sent, awaiting response... 200 OK
Length: 1474560 (1.4M) [text/plain]
Saving to: `/dev/null'

100%[==============================================================>] 1,474,560    499K/s   in 2.9s

2010-10-11 18:56:06 (499 KB/s) - `/dev/null' saved [1474560/1474560]

FINISHED --2010-10-11 18:56:06--
Downloaded: 2 files, 2.8M in 5.9s (490 KB/s)

I need to grep the total download speed, that is, the string 490 KB/s. How do I do this?

P.S. May need to account for the case that we will actually download only one file, so there won't be final output starting with FINISHED

like image 228
Nickolai Leschov Avatar asked Oct 11 '10 19:10

Nickolai Leschov


3 Answers

Update, a grep-style version using sed:

wget ... 2>&1 | sed -n '$,$s/.*(\(.*\)).*/\1/p'

Old version:

I thought, it's easier to divide the file size by the download time after the download. ;-)

(/usr/bin/time -p wget ... 2>&1 >/dev/null; ls -l newfile) | \
awk '
   NR==1 {t=$2};
   NR==4 {printf("rate=%f bytes/second\n", $5/t)}
'

The first awk line stores the elapsed real time of "real xx.xx" in variabe t. The second awk line divides the file size (column 5 of ls -l) by the time and outputs this as the rate.

like image 198
Peter G. Avatar answered Sep 20 '22 10:09

Peter G.


This worked for me, using your wget -O /dev/null <resource>

The regex I used was \([0-9.]\+ [KM]B/s\)

But note I had to redirect stderr onto stdout so the command was:

wget -O /dev/null http://example.com/index.html 2>&1 | grep '\([0-9.]\+ [KM]B/s\)'

This allows things like 923 KB/s and 1.4 MB/s


grep just finds matches. To get the value(s) you can use sed instead:

wget -O /dev/null http://example.com/index.html 2>&1 |
    sed -e 's|^.*(\([0-9.]\+ [KM]B/s\)).*$|\1|'
like image 26
Stephen P Avatar answered Sep 19 '22 10:09

Stephen P


This works when only 1 file is being downloaded.

I started using sed to get the speed from wget, but I found it irritating so I switched to grep.

This is my command:

wget ... 2>&1 | grep -o "[0-9.]\+ [KM]*B/s"

The -o option means it only returns that part. It matches 1 or more of the 10 digits then a space. Then optionally K or M before the B/s

That will return 423 KB/s (for example).

To grep for just the units, use grep -o "[KM]*B/s" and for just the number use grep -o "[0123456789]\+.

like image 42
Tim Avatar answered Sep 19 '22 10:09

Tim