How to get Xmllint to read from stdin?

Question

• I don't want to create an XML file
• I need to use the --shell with cat to create filters

• I don't have xpath in my version of xmllint, using libxml2-2.7.6-14.el6.x86_64

  xml|xmllint --shell - <<< $(echo 'cat /')

  -:1: parser error : Start tag expected, '<' not found

EDIT: clustat -x outputs an XML file and I want to parse out the active node. I don't think there is a way to do it without xpath so I created a temp xml file.

/usr/sbin/clustat -x > /tmp/clustat.xml ACTIVENODE=$(xmllint --shell /tmp/clustat.xml <<< `echo 'cat //group/@owner'`|grep -v "^/ >"|cut -d= -f2|tr -d \") 

Answer 1

I had a similar issue where I had to unzip an XML file then feed it to xmllint. The key is the "-" option which tells xmllint to read from stdin.

For example:

$ bzip2 -dc dierehabilitati00delagoog_meta.xml.bz2 | xmllint --format 

would fail giving the "usage" for xmllint. Adding "-" worked:

$ bzip2 -dc dierehabilitati00delagoog_meta.xml.bz2 | xmllint --format - <?xml version="1.0"?> <metadata>   <title>Die Rehabilitation im Strafrecht</title>   <creator>Ernst Delaquis</creator>   <mediatype>texts</mediatype>   <collection>americana</collection> </metadata> 

Hope this helps.