I am studying a java tutorial and saw that the way to find the x/y indexes of a JButton inside a GridLayout is to traverse a bidimensional array of buttons b which is associated to the layout and checking if
b[i][j] == buttonReference
.
@Override
public void actionPerformed(ActionEvent ae) {
JButton bx = (JButton) ae.getSource();
for (int i = 0; i < 5; i++)
for (int j = 0; j < 5; j++)
if (b[i][j] == bx)
{
bx.setBackground(Color.RED);
}
}
Is there an easier way to get the X/Y indexes of a button?
Something like:
JButton button = (JButton) ev.getSource();
int x = this.getContentPane().getComponentXIndex(button);
int y = this.getContentPane().getComponentYIndex(button);
this
being a GameWindow instance and ev
the ActionEvent triggered when the user presses the button.
In this case it should get: x == 2, y == 1
@GameWindow.java:
package javaswingapplication;
import java.awt.Color;
import java.awt.GridLayout;
import java.awt.event.*;
import javax.swing.*;
public class GameWindow extends JFrame implements ActionListener
{
JButton b[][] = new JButton[5][5];
int v1[] = { 2, 5, 3, 7, 10 };
int v2[] = { 3, 5, 6, 9, 12 };
public GameWindow(String title)
{
super(title);
setLayout(new GridLayout(5, 5));
setDefaultCloseOperation(EXIT_ON_CLOSE );
for (int i = 0; i < 5; i++)
for (int j = 0; j < 5; j++)
{
b[i][j] = new JButton();
b[i][j].addActionListener(this);
add(b[i][j]);
}
}
@Override
public void actionPerformed(ActionEvent ae) {
((JButton)ae.getSource()).setBackground(Color.red);
}
}
@JavaSwingApplication.java:
package javaswingapplication;
public class JavaSwingApplication {
public static void main(String[] args) {
GameWindow g = new GameWindow("Game");
g.setVisible(true);
g.setSize(500, 500);
}
}
int getRows(): Similar to getColumns() method, we can use it to get the number of rows present in the grid layout.
Creates a grid layout with the specified number of rows and columns. All components in the layout are given equal size. One, but not both, of rows and cols can be zero, which means that any number of objects can be placed in a row or in a column.
Constructors of GridLayout classGridLayout(int rows, int columns): creates a grid layout with the given rows and columns but no gaps between the components.
This example shows how to create a grid button that knows its location on the grid. The method getGridButton()
shows how to obtain a button reference efficiently based on its grid coordinates, and the action listener shows that the clicked and found buttons are identical.
package gui;
import java.awt.EventQueue;
import java.awt.GridLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.ArrayList;
import java.util.List;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;
/**
* @see http://stackoverflow.com/questions/7702697
*/
public class GridButtonPanel {
private static final int N = 5;
private final List<JButton> list = new ArrayList<JButton>();
private JButton getGridButton(int r, int c) {
int index = r * N + c;
return list.get(index);
}
private JButton createGridButton(final int row, final int col) {
final JButton b = new JButton("r" + row + ",c" + col);
b.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
JButton gb = GridButtonPanel.this.getGridButton(row, col);
System.out.println("r" + row + ",c" + col
+ " " + (b == gb)
+ " " + (b.equals(gb)));
}
});
return b;
}
private JPanel createGridPanel() {
JPanel p = new JPanel(new GridLayout(N, N));
for (int i = 0; i < N * N; i++) {
int row = i / N;
int col = i % N;
JButton gb = createGridButton(row, col);
list.add(gb);
p.add(gb);
}
return p;
}
private void display() {
JFrame f = new JFrame("GridButton");
f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
f.add(createGridPanel());
f.pack();
f.setLocationRelativeTo(null);
f.setVisible(true);
}
public static void main(String[] args) {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
new GridButtonPanel().display();
}
});
}
}
You have saved an array of all JButtons; you could search for ae.getSource()
and you have the position.
for (int i = 0; i < 5; i++) {
for (int j = 0; j < 5; j++) {
if( b[i][j] == ae.getSource() ) {
// position i,j
}
}
}
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