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How to get the unique ID of an object which overrides hashCode()?

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What is a hashCode() used for how is it related to a equals b)?

The hashcode() method returns the same hash value when called on two objects, which are equal according to the equals() method. And if the objects are unequal, it usually returns different hash values.

What is object ID in Java?

ObjectId(int timestamp, int machineIdentifier, short processIdentifier, int counter) Creates an ObjectId using the given time, machine identifier, process identifier, and counter. ObjectId(java.lang.String hexString) Constructs a new instance from a 24-byte hexadecimal string representation.

What is the default implementation of hashCode in Java?

In Java, hashCode() by default is a native method, which means that the method has a modifier 'native', when it is implemented directly in the native code in the JVM. Used to digest all the data stored in an instance of the class into a single hash value i.e., a 32-bit signed integer.

What will be behavior If we override hashCode() method to always return 1?

Only Override HashCode, Use the default Equals: Only the references to the same object will return true. In other words, those objects you expected to be equal will not be equal by calling the equals method.


System.identityHashCode(yourObject) will give the 'original' hash code of yourObject as an integer. Uniqueness isn't necessarily guaranteed. The Sun JVM implementation will give you a value which is related to the original memory address for this object, but that's an implementation detail and you shouldn't rely on it.

EDIT: Answer modified following Tom's comment below re. memory addresses and moving objects.


The javadoc for Object specifies that

This is typically implemented by converting the internal address of the object into an integer, but this implementation technique is not required by the JavaTM programming language.

If a class overrides hashCode, it means that it wants to generate a specific id, which will (one can hope) have the right behaviour.

You can use System.identityHashCode to get that id for any class.


hashCode() method is not for providing a unique identifier for an object. It rather digests the object's state (i.e. values of member fields) to a single integer. This value is mostly used by some hash based data structures like maps and sets to effectively store and retrieve objects.

If you need an identifier for your objects, I recommend you to add your own method instead of overriding hashCode. For this purpose, you can create a base interface (or an abstract class) like below.

public interface IdentifiedObject<I> {
    I getId();
}

Example usage:

public class User implements IdentifiedObject<Integer> {
    private Integer studentId;

    public User(Integer studentId) {
        this.studentId = studentId;
    }

    @Override
    public Integer getId() {
        return studentId;
    }
}

Maybe this quick, dirty solution will work?

public class A {
    static int UNIQUE_ID = 0;
    int uid = ++UNIQUE_ID;

    public int hashCode() {
        return uid;
    }
}

This also gives the number of instance of a class being initialized.


If it's a class that you can modify, you could declare a class variable static java.util.concurrent.atomic.AtomicInteger nextInstanceId. (You'll have to give it an initial value in the obvious way.) Then declare an instance variable int instanceId = nextInstanceId.getAndIncrement().