How to get the PYTHONPATH in shell?

Question

debian@debian:~$ echo $PYTHONPATH   /home/qiime/lib/:   debian@debian:~$ python   Python 2.7.3 (default, Jan  2 2013, 16:53:07)    [GCC 4.7.2] on linux2   Type "help", "copyright", "credits" or "license" for more information.   >>> import sys   >>> sys.path   ['', '/usr/local/lib/python2.7/dist-packages/feedparser-5.1.3-py2.7.egg',    '/usr/local/lib/python2.7/dist-packages/stripogram-1.5-py2.7.egg', '/home/qiime/lib',  '/home/debian', '/usr/lib/python2.7', '/usr/lib/python2.7/plat-linux2',    '/usr/lib/python2.7/lib-tk', '/usr/lib/python2.7/lib-old', '/usr/lib/python2.7/lib- dynload',   '/usr/local/lib/python2.7/dist-packages', '/usr/lib/python2.7/dist-packages',  '/usr/lib/python2.7/dist-packages/PIL', '/usr/lib/python2.7/dist-packages/gst-0.10',   '/usr/lib/python2.7/dist-packages/gtk-2.0', '/usr/lib/pymodules/python2.7']     

How can I get all of PYTHONPATH output in bash?
Why echo $PYTHONPATH can not get all of them?

Answer 1

The environment variable PYTHONPATH is actually only added to the list of locations Python searches for modules. You can print out the full list in the terminal like this:

python -c "import sys; print(sys.path)" 

Or if want the output in the UNIX directory list style (separated by :) you can do this:

python -c "import sys; print(':'.join(x for x in sys.path if x))" 

Which will output something like this:

/usr/local/lib/python2.7/dist-packages/feedparser-5.1.3-py2.7.egg:/usr/local/lib/ python2.7/dist-packages/stripogram-1.5-py2.7.egg:/home/qiime/lib:/home/debian:/us r/lib/python2.7:/usr/lib/python2.7/plat-linux2:/usr/lib/python2.7/lib-tk:/usr/lib /python2.7/lib-old:/usr/lib/python2.7/lib- dynload:/usr/local/lib/python2.7/dist- packages:/usr/lib/python2.7/dist-packages:/usr/lib/python2.7/dist-packages/PIL:/u sr/lib/python2.7/dist-packages/gst-0.10:/usr/lib/python2.7/dist-packages/gtk-2.0: /usr/lib/pymodules/python2.7