If we have a list, and each item can have different length. For example:
l <- list(c(1, 2), c(3, 4,5), c(5), c(6,7))
(In order to be clear, we will call objects in a list "items", and objects in the objects of list "elements".)
How can we extract, for example the first element of each item? Here, I want to extract:
1, 3, 5, 6
Then same question for the second element of each item:
2, 4, NA, 7
Use list indexing to get the nth element of a list. Use list indexing syntax list[index] with n - 1 as index , where n represents a value's placement in the list, to retrieve the respective nth element of a list.
To extract only first element from a list, we can use sapply function and access the first element with double square brackets. For example, if we have a list called LIST that contains 5 elements each containing 20 elements then the first sub-element can be extracted by using the command sapply(LIST,"[[",1).
We can create a function using sapply
fun1 <- function(lst, n){
sapply(lst, `[`, n)
}
fun1(l, 1)
#[1] 1 3 5 6
fun1(l, 2)
#[1] 2 4 NA 7
data.table::transpose(l)
will give you a list with vectors of all 1st elements, all 2nd elements, etc.
l <- list(1:2, 3:4, 5:7, 8:10)
b <- data.table::transpose(l)
b
# [[1]]
# [1] 1 3 5 8
#
# [[2]]
# [1] 2 4 6 9
#
# [[3]]
# [1] NA NA 7 10
If you don't want the NAs you can do lapply(b, function(x) x[!is.na(x)])
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