How to get the most recent file using a batch file?

Question

I have a list of zip files with date and time appended like yyyymmdd_hhmmss_Demos.zip. Now how to get the most recently added zip file in the source dir. I need to copy this file in the target using copy command.

I found some info about forfiles, but do not have an idea on how to get it done for seconds.

Answer 1

You can use

pushd D:\a
for /f "tokens=*" %%a in ('dir /b /od') do set newest=%%a
copy "%newest%" D:\b
popd

Answer 2

set Path="D:\hello\abc\old"
for /f "tokens=*" %%a in ('dir /A:-D /B /O:-D /S %Path%') do set NEW=%%a&& goto:n 
:n
echo %NEW%

Answer 3

pushd \\ryap\CONTROL_DATOS
for /f "tokens=*" %%a in ('dir \\ryap\CONTROL_DATOS /b /od') do set newest=%%a
Xcopy/Y "\\ryap\CONTROL_DATOS\%newest%" "D:\TXT_SOURCES\"
popd