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How to get the LAN IP of a client using Java?

How can i get the LAN IP-address of a computer using Java? I want the IP-address which is connected to the router and the rest of the network.

I've tried something like this:

Socket s = new Socket("www.google.com", 80);
String ip = s.getLocalAddress().getHostAddress();
s.close();

This seem to work on some cases, but sometimes it returns the loopback-address or something completely different. Also, it requires internet connection.

Does anyone got a more accurate method of doing this?

EDIT: Thought it would be better to ask here than in a comment..

What if you got many interfaces? For example, one for cable, one for wifi and one for virtual box or so. Is it impossible to actually see which one is connected to the network?

like image 674
cragiz Avatar asked May 16 '10 20:05

cragiz


3 Answers

Try java.net.NetworkInterface

import java.net.NetworkInterface;

...

for (
    final Enumeration< NetworkInterface > interfaces =
        NetworkInterface.getNetworkInterfaces( );
    interfaces.hasMoreElements( );
)
{
    final NetworkInterface cur = interfaces.nextElement( );

    if ( cur.isLoopback( ) )
    {
        continue;
    }

    System.out.println( "interface " + cur.getName( ) );

    for ( final InterfaceAddress addr : cur.getInterfaceAddresses( ) )
    {
        final InetAddress inet_addr = addr.getAddress( );

        if ( !( inet_addr instanceof Inet4Address ) )
        {
            continue;
        }

        System.out.println(
            "  address: " + inet_addr.getHostAddress( ) +
            "/" + addr.getNetworkPrefixLength( )
        );

        System.out.println(
            "  broadcast address: " +
                addr.getBroadcast( ).getHostAddress( )
        );
    }
}
like image 138
Alexander Pogrebnyak Avatar answered Nov 15 '22 07:11

Alexander Pogrebnyak


At first: There is no single address. Your machine has at least two adresses (127.0.0.1 on "lo" and maybe 192.168.1.1 on "eth1").

You want this: Listing network interfaces

As you may expect, you cannot automatically detect which one is connected to any of your routers, since this needs potentially complex parsing of your routing tables. But if you just want any non-local address this should be enought. To be sure, try to use this at least one time on vista or Windows 7, since they add IPv6 addresses.

import java.io.*;
import java.net.*;
import java.util.*;
import static java.lang.System.out;

public class ListNets 
{
    public static void main(String args[]) throws SocketException {
        Enumeration<NetworkInterface> nets = NetworkInterface.getNetworkInterfaces();
        for (NetworkInterface netint : Collections.list(nets))
            displayInterfaceInformation(netint);
    }

    static void displayInterfaceInformation(NetworkInterface netint) throws SocketException {
        out.printf("Display name: %s\n", netint.getDisplayName());
        out.printf("Name: %s\n", netint.getName());
        Enumeration<InetAddress> inetAddresses = netint.getInetAddresses();
        for (InetAddress inetAddress : Collections.list(inetAddresses)) {
            out.printf("InetAddress: %s\n", inetAddress);
        }
        out.printf("\n");
     }
}  

The following is sample output from the example program:

Display name: bge0
Name: bge0
InetAddress: /fe80:0:0:0:203:baff:fef2:e99d%2
InetAddress: /121.153.225.59

Display name: lo0
Name: lo0
InetAddress: /0:0:0:0:0:0:0:1%1
InetAddress: /127.0.0.1
like image 26
Daniel Avatar answered Nov 15 '22 07:11

Daniel


This is a method I've used for a while. It includes a little hack to figure out the externally visible ip-address as well.

private List<String> getLocalHostAddresses() {

    List<String> addresses = new ArrayList<String>();

    try {
        Enumeration<NetworkInterface> e = NetworkInterface.getNetworkInterfaces();

        while (e.hasMoreElements()) {
            NetworkInterface ni = e.nextElement();
            Enumeration<InetAddress> e2 = ni.getInetAddresses();
            while (e2.hasMoreElements())
                addresses.add(e2.nextElement().getHostAddress());
        }
        URL u = new URL("http://whatismyip.org");
        BufferedReader in = new BufferedReader(new InputStreamReader(
                u.openStream()));
        addresses.add(in.readLine());
        in.close();
    } catch (Exception ignore) {
    }

    return addresses;
}
like image 1
aioobe Avatar answered Nov 15 '22 06:11

aioobe