How to get string from several double quotes in a line?

Question

Basically, I need to get a b c (separately)

from a line (with any amount of spaces between each "

"a" "b" "c"

Is it possible to do this using string.split?

I've tried everything from split(".*?\".*?") to ("\\s*\"\\s*").

The latter works, but it splits the data into every other index of the array (1, 3, 5) with the other ones being empty ""

Edit:

I'd like for this to apply with any amount/variation of characters, not just a, b and c. (example: "apple" "pie" "dog boy")

Found a solution for my specific problem (might not be most efficient):

Scanner abc = new Scanner(System.in);
for loop
{
      input = abc.nextLine();
      Scanner in= new Scanner(input).useDelimiter("\\s*\"\\s*");
      assign to appropriate index in array using in.next();
      in.next(); to avoid the spaces
}

Answer 1

You can use pattern instead :

String str = "\"a\" \"b\" \"c\" \"\"";
Pattern pat = Pattern.compile("\"[a-z]+\"");
Matcher mat = pat.matcher(str);

while (mat.find()) {
    System.out.println(mat.group());
}

For inputs like this "a" "b" "c" "" then the :

Output

"a"
"b"
"c"

---

If you want to get a b c without quotes you can use :

String str = "\"a\" \"b\" \"c\" \"\"";
Pattern pat = Pattern.compile("\"([a-z]+)\"");
Matcher mat = pat.matcher(str);

while (mat.find()) {
    System.out.println(mat.group(1));
}

Output

a
b
c

---

String with spaces

If you can have spaces between quotes you can use \"([a-z\\s]+)\"

String str = "\"a\" \"b\" \"c include spaces \" \"\"";
Pattern pat = Pattern.compile("\"([a-z\\s]+)\"");
Matcher mat = pat.matcher(str);

while (mat.find()) {
    System.out.println(mat.group(1));
}

Output

a
b
c include spaces

Ideone