Part of my project, where we have to take an input file with hex numbers and convert them to MIPS code, I want to convert the hex into binary so it'd be easier for me to convert it into MIPS. However, when I run the code, it crashes and quits when it reaches the part where it calls the converter function. GDB says its a critical error c0000374. How do I fix this?
I have tried giving the target string more space and it doesn't seem to have any effect. I have also tried using malloc to no avail.
char* convertBinary (int hex)
{
char* hexdec = calloc(9, sizeof(char));
char* bin = calloc(SIZE+1, sizeof(char));
snprintf(hexdec, SIZE, "%08X", hex);
long int i;
for (i = 0; hexdec[i]; ++i)
{
switch (hexdec[i])
{
case '0':
strcat(bin, "0000");
break;
case '1':
strcat(bin, "0001");
break;
case '2':
strcat(bin, "0010");
break;
case '3':
strcat(bin, "0011");
break;
case '4':
strcat(bin, "0100");
break;
case '5':
strcat(bin, "0101");
break;
case '6':
strcat(bin, "0110");
break;
case '7':
strcat(bin, "0111");
break;
case '8':
strcat(bin, "1000");
break;
case '9':
strcat(bin, "1001");
break;
case 'A':
case 'a':
strcat(bin, "1010");
break;
case 'B':
case 'b':
strcat(bin, "1011");
break;
case 'C':
case 'c':
strcat(bin, "1100");
break;
case 'D':
case 'd':
strcat(bin, "1101");
break;
case 'E':
case 'e':
strcat(bin, "1110");
break;
case 'F':
case 'f':
strcat(bin, "1111");
break;
default:
printf("\nInvalid hexadecimal digit %c",
hexdec[i]);
}
}
return bin;
}
Also, in case it helps, here is the main function where I call this function
int main ()
{
int command = 10010100; //This is in hex
char* binaryString = convertBinary(command);
printf("The coverted binary is: %s\n", binaryString);
}
I expect the function to return a string of the binary numbers that have been converted from an 8 digit hex number. However, the program just quits and doesn't output anything. When debugged with GDB, it lays out a warning saying,
warning: Critical error detected c0000374
There are multiple problems in your code:
Since you allocate 9 bytes for hexdec
, snprintf(hexdec, SIZE, "%08X", hex);
should be
snprintf(hexdec, 9, "%08X", hex);
The definition of SIZE
is missing, as well as the #include
lines. Post the complete source of the program exhibiting the offending behavior.
There is no need to loop until the end of the string hexdec
: since you convert the hex
value with %08X
, just loop with:
for (i = 0; i < 8; ++i)
You should free(hexdec)
before leaving the convertBinary
function.
int command = 10010100; //This is in hex
, which one is wrong? Probably both.long
type for i
, int
will suffice. Conversely, the argument hex
should have unsigned int
type.Here is a simplified version of your code:
#include <stdio.h>
#include <stdlib.h>
char *convertBinary(unsigned int hex) {
char *bin = calloc(33, 1);
int i;
if (bin) {
for (i = 32; i-- > 0;) {
bin[i] = '0' + (hex & 1);
hex >>= 1;
}
}
return bin;
}
int main() {
int command = 0x10010100; //This is in hex
char *binaryString = convertBinary(command);
if (binaryString == NULL) {
printf("Memory allocation failure\n");
} else {
printf("The converted binary is: %s\n", binaryString);
free(binaryString);
}
return 0;
}
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