I am trying to get name of a File
object without its extension, e.g. getting "vegetation" when the filename is "vegetation.txt." I have tried implementing this code:
openFile = fileChooser.getSelectedFile(); String[] tokens = openFile.getName().split("."); String name = tokens[0];
Unfortunately, it returns a null
object. There is a problem just in the defining the String
object, I guess, because the method getName()
works correctly; it gives me the name of the file with its extension.
Do you have any idea?
GetFileNameWithoutExtension(ReadOnlySpan<Char>) Returns the file name without the extension of a file path that is represented by a read-only character span.
If you are using the Gauva Library, you can directly use the getFileExtension() method to get the file extension. For example, String fileName = "Test. java"; String extension = Files.
If you want to implement this yourself, try this:
String name = file.getName(); int pos = name.lastIndexOf("."); if (pos > 0) { name = name.substring(0, pos); }
(This variation doesn't leave you with an empty string for an input filename like ".txt". If you want the string to be empty in that case, change > 0
to >= 0
.)
You could replace the if
statement with an assignment using a conditional expression, if you thought it made your code more readable; see @Steven's answer for example. (I don't think it does ... but it is a matter of opinion.)
It is arguably a better idea to use an implementation that someone else has written and tested. Apache FilenameUtils
is a good choice; see @slachnick's Answer, and also the linked Q&A.
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