I want to display the short name for each month, 12 months back from the previous month, but with the below I get an error on mon1 and mon2 and I guess since that is last year?
mon1=MonthName(Month(Now())-11,1)
mon2=MonthName(Month(Now())-10,1)
mon3=MonthName(Month(Now())-9,1)
mon4=MonthName(Month(Now())-8,1)
mon5=MonthName(Month(Now())-7,1)
mon6=MonthName(Month(Now())-6,1)
mon7=MonthName(Month(Now())-5,1)
mon8=MonthName(Month(Now())-4,1)
mon9=MonthName(Month(Now())-3,1)
mon10=MonthName(Month(Now())-2,1)
mon11=MonthName(Month(Now())-1,1)
mon12=MonthName(Month(Now()),1)
So how can I display now,dec,jan,feb,mar,apr,may,jun,jul,aug,sep,oct Thanks.
The problem here is the Month() function returns an integer between 1 and 12 to represent each month. Instead you want to minus the number of months from the Now() value before wrapping it with Month().
Below is an example that does this using a For loop and a single dimension Array.
Dim dt: dt = Now()
Dim i, mon(12)
Const numOfMonths = 12
For i = 1 To numOfMonths
mon(i) = MonthName(Month(DateAdd("m", i - numOfMonths, dt)), True)
Next
Call Response.Write(Join(mon, vbCrLf))
Output:
Sep
Aug
Jul
Jun
May
Apr
Mar
Feb
Jan
Dec
Nov
Oct
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With