How to get Method Name of Generic Func<T> passed into Method

Question

I'm trying to get the method name of a function passed into an object using a .Net closure like this:

Method Signature

public IEnumerable<T> GetData<T>(Func<IEnumerable<T>> WebServiceCallback) 
where T : class    
{
    // either gets me '<LoadData>b__3'
    var a = nrdsWebServiceCallback.Method.Name;
    var b = nrdsWebServiceCallback.GetInvocationList();

    return WebServiceCallback();
}

I'm calling it like this:

SessionStateService.Labs = CacheManager.GetData(() =>  
WCFService.GetLabs(SessionStateService.var1, SessionStateService.var2));

Seeing 'b__3' instead of WCFServce.GetLabs(..) etc

Answer 1

You're looking at the name of the lambda expression (generated by the compiler), instead of the name of the method called inside the lambda.

You have to use an <Expression<Func<T>> instead of a Func<T>. Expressions can be parsed and analyzed.

Try

public IEnumerable<T> GetData<T>(Expression<Func<IEnumerable<T>>> callbackExpression) 
where T : class    
{
    var methodCall = callbackExpression.Body as MethodCallExpression;
    if(methodCall != null)
    {
        string methodName = methodCall.Method.Name;
    }

    return callbackExpression.Compile()();
}

Answer 2

What is actually passed into your function is an anonymous lambda function (() => WCFService.Etc), so what you're seeing is the actual method name - <LoadData>b__3 is the autogenerated name for the anonymous method.

What you actually want is the method called inside the method called. For that, you need to delve into expressions. Instead of Func<IEnumerable<T>>, define your parameter as Expression<Func<IEnumerable<T>>>, and call this code:

var body = nrdsWebServiceCallback.Body as MethodCallExpression;
if (body != null)
   Console.WriteLine(body.Method.DeclaringType.Name + "." + body.Method.Name);