How to get list of pattern string and matcher string in java regex

Question

First time I use Regex statement.

I have java regex statement, which split String by pattern with list of some characters.

String line = "F01T8B02S00003H04Z05C0.12500";
Pattern pattern = Pattern.compile("([BCFHSTZ])");
String[] commands = pattern.split(line);

for (String command : commands) {
 System.out.print(command);
}

output of above code is like (018020000304050.12500)

Actually I want output like this, ("F", "01", "T", "8", "B", "02", "S", "00003", "H", "04", "Z", "05", "C", "0.12500").

Means desired output is contains pattern character and split value both.

Can you please suggest me?

Answer 1

I've created a sample, try it and let me know if it's what you want.

public class Main {

public static void main(String[] args) {

    String line = "F01T8B02S00003H04Z05C0.12500";
    String pattern = "([A-Z][a-z]*)(((?=[A-Z][a-z]*|$))|\\d+(\\.\\d+)?)";

    Pattern r = Pattern.compile(pattern);

    Matcher m = r.matcher(line);
    HashMap<String, String> mHash = new LinkedHashMap<>();

    while (m.find()) {
        mHash.put(m.group(1), m.group(2));
    }

    System.out.println(mHash.toString());

}

}

Output is:

F 01
T 8
B 02
S 00003
H 04
Z 05
C 0.12500

Edit with LinkedHashMap

public class Main {

    public static void main(String[] args) {

        String line = "F01T8B02S00003H04Z05C0.12500";
        String pattern = "([A-Z][a-z]*)(((?=[A-Z][a-z]*|$))|\\d+(\\.\\d+)?)";

        Pattern r = Pattern.compile(pattern);

        Matcher m = r.matcher(line);
        HashMap<String, String> mHash = new LinkedHashMap<>();

        while (m.find()) {
            mHash.put(m.group(1), m.group(2));
        }

        System.out.println(mHash.toString());

    }
}

Output is :

{F=01, T=8, B=02, S=00003, H=04, Z=05, C=0.12500}