I want to get last record of each day in mysql.Location<id, date, place_id>
table has multiple entries on each day. This Location table has place_id and time at which place_id is inserted.
Also taking consider if place_id is not present then return second last record which has place_id. In following table for NULL, '2016-04-06 18:52:06'
record we are returning '13664', '2016-04-06 12:57:30'
, which is second last record on '2016-04-06' (6th March) and has place_id.
One more thing, on single day, there would be more place_id, see the following table..
id || place_id || date
'1', '47', '2016-04-05 18:09:37'
'2', '48', '2016-04-05 12:09:37'
'3', '13664', '2016-04-06 12:57:30'
'4', '9553', '2016-04-08 10:09:37'
'5', NULL, '2016-04-06 18:52:06'
'6', '9537', '2016-04-07 03:34:24'
'7', '9537', '2016-04-07 03:34:24'
'8', '656', '2016-04-07 05:34:24'
'9', '7', '2016-04-07 05:34:57'
When I run following query it returns following result
Query I run the following query but it is giving me wrong result
`Location<id, place_id, date>`
select L1.place_id, L1.date from
Location1 L1
Left join
Location1 L2
on
Date(L1.date) = Date(L2.date)
And
L1.date < L2.date
where
L2.date is null
group by L1.date;
Result I want:
id....place_id ........date
'1', '47', '2016-04-05 18:09:37'
'3', '13664', '2016-04-06 12:57:30'
'4', '9553', '2016-04-08 10:09:37'
'9', '7', '2016-04-07 05:34:57'
We use system function now() to get the latest datetime value, and INTERVAL clause to calculate a date 7 days in the past.
To get yesterday's date, you need to subtract one day from today's date. Use CURDATE() to get today's date. In MySQL, you can subtract any date interval using the DATE_SUB() function. Here, since you need to subtract one day, you use DATE_SUB(CURDATE(), INTERVAL 1 DAY) to get yesterday's date.
The LAST_DAY() function extracts the last day of the month for a given date.
To get the last record, the following is the query. mysql> select *from getLastRecord ORDER BY id DESC LIMIT 1; The following is the output. The above output shows that we have fetched the last record, with Id 4 and Name Carol.
You may give it a try:
SELECT
L.id,
L.place_id,
L.date
FROM Location L
INNER JOIN
(
SELECT
MAX(date) max_time
FROM Location
GROUP BY Date(`date`)
) AS t
ON L.date = t.max_time
SQL FIDDLE DEMO
SQL FIDDLE DEMO2
[Based on your expected output]
Can you try with the following query:
SELECT * FROM `Location` GROUP BY DATE(`date`) ORDER BY `date` DESC
What this query does is group the rows by descending date and show a row for each date.
Get the last record:
SELECT * FROM `Location` ORDER BY `date` LIMIT 1;
Get the last record that doesn't have a null as a value:
SELECT * FROM `Location` WHERE place_id IS NOT NULL ORDER BY `date` LIMIT 1;
Get records for all the places which are not null:
SELECT * FROM `Location` WHERE place_id IS NOT NULL GROUP BY `place_id` ORDER BY `date` DESC
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