I am using Git and working on master
branch. This branch has a file called app.js
.
I have an experiment
branch in which I made a bunch of changes and tons of commits. Now I want to bring all the changes done only to app.js
from experiment
to master
branch.
How do I do that?
Once again I do not want a merge. I just want to bring all the changes in app.js
from experiment
branch to master
branch.
Short Answergit checkout origin/master -- path/to/file // git checkout <local repo name (default is origin)>/<branch name> -- path/to/file will checkout the particular file from the downloaded changes (origin/master).
You can't clone a single file using git. Git is a distributed version control system, the Idea behind its clone functionality is to have a complete copy of project and all versions of files related to that project.
git checkout master # first get back to master git checkout experiment -- app.js # then copy the version of app.js # from branch "experiment"
See also git how to undo changes of one file?
With the new git switch
and git restore
commands, that would be:
git switch master git restore --source experiment -- app.js
By default, only the working tree is restored.
If you want to update the index as well (meaning restore the file content, and add it to the index in one command):
git restore --source experiment --staged --worktree -- app.js # shorter: git restore -s experiment -SW -- app.js
As Jakub Narębski mentions in the comments:
git show experiment:path/to/app.js > path/to/app.js
works too, except that, as detailed in the SO question "How to retrieve a single file from specific revision in Git?", you need to use the full path from the root directory of the repo.
Hence the path/to/app.js used by Jakub in his example.
As Frosty mentions in the comment:
you will only get the most recent state of app.js
But, for git checkout
or git show
, you can actually reference any revision you want, as illustrated in the SO question "git checkout revision of a file in git gui":
$ git show $REVISION:$FILENAME $ git checkout $REVISION -- $FILENAME
would be the same is $FILENAME is a full path of a versioned file.
$REVISION
can be as shown in git rev-parse
:
experiment@{yesterday}:app.js # app.js as it was yesterday experiment^:app.js # app.js on the first commit parent experiment@{2}:app.js # app.js two commits ago
and so on.
schmijos adds in the comments:
you also can do this from a stash:
git checkout stash -- app.js
This is very useful if you're working on two branches and don't want to commit.
Everything is much simpler, use git checkout for that.
Suppose you're on master
branch, to get app.js from new-feature
branch do:
git checkout new-feature path/to/app.js // note that there is no leading slash in the path!
This will bring you the contents of the desired file. You can, as always, use part of sha1 instead of new-feature branch name to get the file as it was in that particular commit.
Note:new-feature
needs to be a local branch, not a remote one.
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