How to get index of XCUIElement in XCUIElementQuery?

Question

This is my simple UITest (customizing order of tabs in tabbarcontroller):

func testIsOrderOfTabsSaved() {

    let app = XCUIApplication()
    let tabBarsQuery = app.tabBars
    tabBarsQuery.buttons["More"].tap()
    app.navigationBars["More"].buttons["Edit"].tap()
    tabBarsQuery.buttons["Takeaway"].swipeLeft()
    tabBarsQuery.buttons["In Restaurant"].swipeLeft()

    //here, how to get position of moved button with text "In Restaurant"?

NOTE:

It is possible to get XCUIElement from XCUIElementQuery by index. Can I do this fro the other way?

Answer 1

It seems that the queries automatically return in order based on position on screen.

for i in 0...tabsQuery.buttons.count {
    let ele = tabsQuery.buttons.elementBoundByIndex(i)
}

Where the index i represents the position of the button in the tab bar, 0 being the leftmost tab, i == tabsQuery.buttons.count being the rightmost.

Answer 2

You have various ways to create a position test. The simplest way is to get buttons at indices 0 and 1, then get two buttons by name and compare the arrays are equal: (written without testing)

 let buttonOrder = [tabBarsQuery.buttons.elementAtIndex(0), tabBarsQuery.buttons.elementAtIndex(1)]

 let takeawayButton = buttons["Takeaway"];
 let restaurantButton = buttons["In Restaurant"];

 XCTAssert(buttonOrder == [takeawayButton, restaurantButton])

Another option is to directly get the frame of each button and assert that one X coordinate is lower than the other.

To answer your specific question about getting the index of an XCUIElement in a XCUIElementQuery, that's absolutely possible. Just go through all the elements in the query and return the index of the first one equal to the element.