How to get first 3 parts of URL in PHP?

Question

How to get first 3 parts of current URL by using PHP.

For example:

My Url: http://something.com/somebody/somegirls/whatever/

The result after getting parts: http://something.com/somebody/somegirls/

This is my code PHP which get current URL:

<?php   function curPageURL() {
        $url  = isset( $_SERVER['HTTPS'] ) && 'on' === $_SERVER['HTTPS'] ? 'https' : 'http';
        $url .= '://' . $_SERVER['SERVER_NAME'];
        $url .= in_array( $_SERVER['SERVER_PORT'], array('80', '443') ) ? '' : ':' . $_SERVER['SERVER_PORT'];
        $url .= $_SERVER['REQUEST_URI'];
        return $url;
    }

 $current_url = str_replace("www.", "", curPageURL());

?>

Answer 1

Try this,

<?php
  $url = 'http://something.com/somebody/somegirls/whatever/';
  $parts = explode('/', $url);
  $new_url = $parts[0].'/'.$parts[1].'/'.$parts[2].'/'.$parts[3].'/'.$parts[4].'/';
  echo $new_url;
?>

OUTPUT

http://something.com/somebody/somegirls/

Answer 2

Assuming that you have grabbed this URL from your function...

<?php
$url='http://www.something.com/somebody/somegirls/whatever/';
$parts=explode('/',parse_url($url)['path']);
array_unshift($parts,trim(strstr(parse_url($url)['host'],'.'),'.'));
print_r(array_filter($parts));

OUTPUT :

Array
(
    [0] => something.com
    [2] => somebody
    [3] => somegirls
    [4] => whatever
)

Demonstration