http://localhost/mc/site-01-up/index.php?c=lorem-ipsum
$address = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$stack = explode('/', $_SERVER["REQUEST_URI"]);
$file = array_pop($stack);
echo $file;
result - index.php?c=lorem-ipsum
How to get just file name (index.php
) without $_GET
variable, using array_pop
if possible?
Another method that can get the filename is by using parse_url — Parses a URL and return its components
<?php
$url = "http://localhost/mc/site-01-up/index.php?c=lorem-ipsum";
$data = parse_url($url);
$array = explode("/",$data['path']);
$filename = $array[count($array)-1];
var_dump($filename);
Result
index.php
EDIT: Sorry for posting this answer as it is almost identical to the selected one. I didnt see the answer so posted. But I cannot delete this as it is seen as a bad practice by moderators.
I will follow parse_url()
like below (easy to understand):-
<?php
$url = 'http://localhost/mc/site-01-up/index.php?c=lorem-ipsum';
$url= parse_url($url);
print_r($url); // to check what parse_url() will outputs
$url_path = explode('/',$url['path']); // explode the path part
$file_name = $url_path[count($url_path)-1]; // get last index value which is your desired result
echo $file_name;
?>
Output:- https://eval.in/606839
Note:- tested with your given URL. Check for other type of URL's at your end. thanks.
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