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How to get the first few lines from a gziped file ? I tried zcat, but its throwing an error
zcat CONN.20111109.0057.gz|head CONN.20111109.0057.gz.Z: A file or directory in the path name does not exist. 
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Just use zcat to see content without extraction. From the manual: zcat is identical to gunzip -c . (On some systems, zcat may be installed as gzcat to preserve the original link to compress .)
How to split a gz file (database dump) into smaller files and move to another server and restore the database dump there? You can split a larger file into smaller pieces using the “split” command.
Grep gz files without unzipping As we showed earlier, you can use the zgrep command to search through compressed files without having to unzip them first. You can also use the zcat command to display the contents of a gz file and then pipe that output to grep to isolate the lines containing your search string.
zcat(1) can be supplied by either compress(1) or by gzip(1). On your system, it appears to be compress(1) -- it is looking for a file with a .Z extension.
Switch to gzip -cd in place of zcat and your command should work fine:
gzip -cd CONN.20111109.0057.gz | head Explanation
-c --stdout --to-stdout Write output on standard output; keep original files unchanged. If there are several input files, the output consists of a sequence of independently compressed members. To obtain better compression, concatenate all input files before compressing them. -d --decompress --uncompress Decompress. On some systems (e.g., Mac), you need to use gzcat.
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