How to get Device UDID in programmatically in iOS7?

Question

How to get device UDID in programatically in iOS7.[[UIDevice currentDevice] uniqueIdentifier] I was used this code This is deprecated iOS7. how to get the device UDID. The UDID String changing when I delete the app and the reinstall means the UDID was getting different one.

Answer 1

It's work 100% to all the version

other best option recommend by apple use ASIdentifierManager Class Reference

ios7-app-backward-compatible-with-ios5-regarding-unique-identifier

this link tell you how to handle and use custom framework

uidevice-uniqueidentifier-property-is-deprecated-what-now

iOS 9

NSUUID *uuid = [[NSUUID alloc]initWithUUIDString:@"20B0DDE7-6087-4607-842A-E97C72E4D522"]; NSLog(@"%@",uuid); NSLog(@"%@",[uuid UUIDString]); 

or

it support only ios 6.0 and above

code to use [[[UIDevice currentDevice] identifierForVendor] UUIDString];

NSUUID *deviceId; #if TARGET_IPHONE_SIMULATOR deviceId = [NSUUID initWithUUIDString:@"UUID-STRING-VALUE"]; #else deviceId = [UIDevice currentDevice].identifierForVendor; #endif 

ios 5 to use like

 if ([[UIDevice currentDevice] respondsToSelector:@selector(identifierForVendor)]) {     // This is will run if it is iOS6     return [[[UIDevice currentDevice] identifierForVendor] UUIDString]; } else {    // This is will run before iOS6 and you can use openUDID or other     // method to generate an identifier }