I was following this tutorial: Finally, Real-Time Django Is Here: Get Started with Django Channels.
I wanted to extend the app by using Django User objects instead of the handle
variable. But how can I get the current user from the received WebSocket packet in my ws_recieve(message)
function?
I noticed that both the csrftoken
and the first ten digits of sessionid
from the web socket packet match a normal HTTP request. Can I get the current user with this information?
For reference the received packet looks like this:
{'channel': <channels.channel.Channel object at 0x110ea3a20>,
'channel_layer': <channels.asgi.ChannelLayerWrapper object at 0x110c399e8>,
'channel_session': <django.contrib.sessions.backends.db.SessionStore object at 0x110d52cc0>,
'content': {'client': ['127.0.0.1', 52472],
'headers': [[b'connection', b'Upgrade'],
[b'origin', b'http://0.0.0.0:8000'],
[b'cookie',
b'csrftoken=EQLI0lx4SGCpyTWTJrT9UTe1mZV5cbNPpevmVu'
b'STjySlk9ZJvxzHj9XFsJPgWCWq; sessionid=kgi57butc3'
b'zckszpuqphn0egqh22wqaj'],
[b'cache-control', b'no-cache'],
[b'sec-websocket-version', b'13'],
[b'sec-websocket-extensions',
b'x-webkit-deflate-frame'],
[b'host', b'0.0.0.0:8000'],
[b'upgrade', b'websocket'],
[b'sec-websocket-key', b'y2Lmb+Ej+lMYN+BVrSXpXQ=='],
[b'user-agent',
b'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_11_6) '
b'AppleWebKit/602.1.50 (KHTML, like Gecko) Version'
b'/10.0 Safari/602.1.50'],
[b'pragma', b'no-cache']],
'order': 0,
'path': '/chat-message/',
'query_string': '',
'reply_channel': 'websocket.send!UZaOWhupBefN',
'server': ['127.0.0.1', 8000]},
'reply_channel': <channels.channel.Channel object at 0x110ea3a90>}
Updated answer in 2018 via the docs:
To access the user, just use self.scope["user"] in your consumer code:
class ChatConsumer(WebsocketConsumer):
def connect(self, event):
self.user = self.scope["user"]
def receive(self, event):
username_str = None
username = self.scope["user"]
if(username.is_authenticated()):
username_str = username.username
print(type(username_str))
#pdb.set_trace() # optional debugging
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