How to get all sub-elements of an element tree with Python ElementTree?

Question

I want to find a way to get all the sub-elements of an element tree like the way ElementTree.getchildren() does, since getchildren() is deprecated since Python version 2.7.
I don't want to use it anymore, though I can still use it currently.

Answer 1

All sub-elements (descendants) of elem:

all_descendants = list(elem.iter()) 

A more complete example:

>>> import xml.etree.ElementTree as ET >>> a = ET.Element('a') >>> b = ET.SubElement(a, 'b') >>> c = ET.SubElement(a, 'c') >>> d = ET.SubElement(a, 'd') >>> e = ET.SubElement(b, 'e') >>> f = ET.SubElement(d, 'f') >>> g = ET.SubElement(d, 'g') >>> [elem.tag for elem in a.iter()] ['a', 'b', 'e', 'c', 'd', 'f', 'g'] 

To exclude the root itself:

>>> [elem.tag for elem in a.iter() if elem is not a] ['b', 'e', 'c', 'd', 'f', 'g'] 

Answer 2

in the pydoc it is mentioned to use list() method over the node to get child elements.
list(elem)

Answer 3

If you want to get all elements 'a', you can use:

a_lst = list(elem.iter('a'))

If the elem is also 'a', it will be included.