How to get active tab in a Safari App Extension?

Question

When I follow the Apple example I always get a nil activeTab:

override func toolbarItemClicked(in window: SFSafariWindow) {
    // This method will be called when your toolbar item is clicked.

    window.getActiveTab(completionHandler: { (activeTab) in
        print(activeTab)
        activeTab?.getActivePage(completionHandler:  { (activePage) in
            print(activePage)
            activePage?.getPropertiesWithCompletionHandler( { (properties) in
                print(properties)
                if properties?.url != nil {
                    let urlString = properties!.url.absoluteString
                    print("URL!", urlString)
                    let videoURL = self.youtubeDl(urlString: urlString)
                    if videoURL != nil {
                        window.openTab(with: videoURL!, makeActiveIfPossible: true, completionHandler: nil)
                    }
                }
            })
        })
    })
}

Answer 1

Yes there is a getActiveTab:

SFSafariApplication.getActiveWindow { (window) in
    window?.getActiveTab { (tab) in 
        tab?.getActivePage(completionHandler: { (page) in
        }
    }
}

Answer 2

Your Safari App Extension can only access the tabs of sites your extension is configured to access.

In your Info.plist, verify that the SFSafariWebsiteAccess dictionary:

• Has a Level equal to "Some" or "All".

• Has all required domains listed in the Allowed Domains array (if Level="Some").

Be aware that your extension's website access permissions are displayed in Safari > Preferences > Extensions. You are encouraged to limit your website access to "Some" (and explicit domains) unless you really do require access to every website.

Answer 3

You should go to info.plist, NSExtension->SFSafariWebsiteAccess and set something ( for example * - for all sites) to Allowed domains. Without this option, I always got nil from the window. I think your extension doesn't work if the site is not allowed.