How to get a user's Instagram feed

Question

I'd like to get a user's Instagram feed using PHP. I've signed up for an Instagram Developer Account and tried pulling in a user's info and photos, but the response isn't stable. Sometimes I get a response and other times I keep getting the error: access_token is missing. Is there a solid example of getting a user's feed of photos by username?

Ideally, I'd like it to be as simple as:

$instagram = new Instagram();
$photos = $instagram->getPhotos("username-goes-here");

Where Instagram is a class that handles all the requests. Any help or direction is appreciated. Thanks!

Answer 1

Try this,

<?php

  function fetchData($url){
  $ch = curl_init();
  curl_setopt($ch, CURLOPT_URL, $url);
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
  curl_setopt($ch, CURLOPT_TIMEOUT, 20);
  $result = curl_exec($ch);
  curl_close($ch); 
  return $result;
  }

  $result = fetchData("https://api.instagram.com/v1/users/ID-GOES-HERE/media/recent/?access_token=TOKEN-GOES-HERE");
  $result = json_decode($result);
  foreach ($result->data as $post) {
    // Do something with this data.
  }
?>

May this help you.

Answer 2

I did this:

<?php

  function fetchData($url){
  $ch = curl_init();
  curl_setopt($ch, CURLOPT_URL, $url);
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
  curl_setopt($ch, CURLOPT_TIMEOUT, 20);
  $result = curl_exec($ch);
  curl_close($ch); 
  return $result;
  }

  $result = fetchData("https://api.instagram.com/v1/users/USER ID HERE/media/recent/?access_token=ACCES TOKEN HERE&count=14");


  $result = json_decode($result);
  foreach ($result->data as $post) {
     if(empty($post->caption->text)) {
       // Do Nothing
     }
     else {
        echo '<a class="instagram-unit" target="blank" href="'.$post->link.'">
        <img src="'.$post->images->low_resolution->url.'" alt="'.$post->caption->text.'" width="100%" height="auto" />
        <div class="instagram-desc">'.htmlentities($post->caption->text).' | '.htmlentities(date("F j, Y, g:i a", $post->caption->created_time)).'</div></a>';
     }

  }
?>