I have a list of (x,y) values that are not uniformly spaced. Here is the archive used in this question.
I am able to interpolate between the values but what I get are not equispaced interpolating points. Here's what I do:
x_data = [0.613,0.615,0.615,...]
y_data = [5.919,5.349,5.413,...]
# Interpolate values for x and y.
t = np.linspace(0, 1, len(x_data))
t2 = np.linspace(0, 1, 100)
# One-dimensional linear interpolation.
x2 = np.interp(t2, t, x_data)
y2 = np.interp(t2, t, y_data)
# Plot x,y data.
plt.scatter(x_data, y_data, marker='o', color='k', s=40, lw=0.)
# Plot interpolated points.
plt.scatter(x2, y2, marker='o', color='r', s=10, lw=0.5)
Which results in:
As can be seen, the red dots are closer together in sections of the graph where the original points distribution is denser.
I need a way to generate the interpolated points equispaced in x, y according to a given step value (say 0.1)
As askewchan correctly points out, when I mean "equispaced in x, y" I mean that two consecutive interpolated points in the curve should be distanced from each other (euclidean straight line distance) by the same value.
I tried unubtu's answer and it works well for smooth curves but seems to break for not so smooth ones:
This happens because the code calculates the point distance in an euclidean way instead of directly over the curve and I need the distance over the curve to be the same between points. Can this issue be worked around somehow?
The formula is y = y1 + ((x - x1) / (x2 - x1)) * (y2 - y1), where x is the known value, y is the unknown value, x1 and y1 are the coordinates that are below the known x value, and x2 and y2 are the coordinates that are above the x value.
One of the simplest methods is linear interpolation (sometimes known as lerp). Consider the above example of estimating f(2.5). Since 2.5 is midway between 2 and 3, it is reasonable to take f(2.5) midway between f(2) = 0.9093 and f(3) = 0.1411, which yields 0.5252.
What Is Interpolation? Interpolation is a statistical method by which related known values are used to estimate an unknown price or potential yield of a security. Interpolation is achieved by using other established values that are located in sequence with the unknown value.
If a function is only known at a discrete set of data points (xi,yi), interpolation can be used to estimate the value of that function at values of x not included in the data. An interpolation function I(x) passes through the points of a discrete data set, I(xi)=yi.
Convert your xy-data to a parametrized curve, i.e. calculate all all distances between the points and generate the coordinates on the curve by cumulative summing. Then interpolate the x- and y-coordinates independently with respect to the new coordinates.
import numpy as np
from matplotlib import pyplot as plt
data = '''0.615 5.349
0.615 5.413
0.617 6.674
0.617 6.616
0.63 7.418
0.642 7.809
0.648 8.04
0.673 8.789
0.695 9.45
0.712 9.825
0.734 10.265
0.748 10.516
0.764 10.782
0.775 10.979
0.783 11.1
0.808 11.479
0.849 11.951
0.899 12.295
0.951 12.537
0.972 12.675
1.038 12.937
1.098 13.173
1.162 13.464
1.228 13.789
1.294 14.126
1.363 14.518
1.441 14.969
1.545 15.538
1.64 16.071
1.765 16.7
1.904 17.484
2.027 18.36
2.123 19.235
2.149 19.655
2.172 20.096
2.198 20.528
2.221 20.945
2.265 21.352
2.312 21.76
2.365 22.228
2.401 22.836
2.477 23.804'''
data = np.array([line.split() for line in data.split('\n')],dtype=float)
x,y = data.T
xd = np.diff(x)
yd = np.diff(y)
dist = np.sqrt(xd**2+yd**2)
u = np.cumsum(dist)
u = np.hstack([[0],u])
t = np.linspace(0,u.max(),10)
xn = np.interp(t, u, x)
yn = np.interp(t, u, y)
f = plt.figure()
ax = f.add_subplot(111)
ax.set_aspect('equal')
ax.plot(x,y,'o', alpha=0.3)
ax.plot(xn,yn,'ro', markersize=8)
ax.set_xlim(0,5)
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