In Swift, how do you convert an Array to a Tuple?
The issue came up because I am trying to call a function that takes a variable number of arguments inside a function that takes a variable number of arguments.
// Function 1 func sumOf(numbers: Int...) -> Int { var sum = 0 for number in numbers { sum += number } return sum } // Example Usage sumOf(2, 5, 1) // Function 2 func averageOf(numbers: Int...) -> Int { return sumOf(numbers) / numbers.count }
This averageOf
implementation seemed reasonable to me, but it does not compile. It gives the following error when you try to call sumOf(numbers)
:
Could not find an overload for '__converstion' that accepts the supplied arguments
Inside averageOf
, numbers
has the type Int[]
. I believe sumOf
is expecting a Tuple rather than an Array.
Thus, in Swift, how do you convert an Array to a Tuple?
Variadic parameters (Variable Length argument) are Python's solution to that problem. A Variadic Parameter accepts arbitrary arguments and collects them into a data structure without raising an error for unmatched parameters numbers.
A variadic parameter accepts zero or more values of a specified type. You use a variadic parameter to specify that the parameter can be passed a varying number of input values when the function is called.
Variadic functions are functions (e.g. printf) which take a variable number of arguments.
This has nothing to do with tuples. Anyway, it isn't possible to convert from an array to a tuple in the general case, as the arrays can have any length, and the arity of a tuple must be known at compile time.
However, you can solve your problem by providing overloads:
// This function does the actual work func sumOf(_ numbers: [Int]) -> Int { return numbers.reduce(0, +) // functional style with reduce } // This overload allows the variadic notation and // forwards its args to the function above func sumOf(_ numbers: Int...) -> Int { return sumOf(numbers) } sumOf(2, 5, 1) func averageOf(_ numbers: Int...) -> Int { // This calls the first function directly return sumOf(numbers) / numbers.count } averageOf(2, 5, 1)
Maybe there is a better way (e.g., Scala uses a special type ascription to avoid needing the overload; you could write in Scala sumOf(numbers: _*)
from within averageOf
without defining two functions), but I haven't found it in the docs.
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