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How to forcefully close an async generator?

Let's say I have an async generator like this:

async def event_publisher(connection, queue):
    while True:
        if not await connection.is_disconnected():
            event = await queue.get()
            yield event
        else:
            return

I consume it like this:

published_events = event_publisher(connection, queue)
async for event in published_events:
    # do event processing here

It works just fine, however when the connection is disconnected and there is no new event published the async for will just wait forever, so ideally I would like to close the generator forcefully like this:

if connection.is_disconnected():
    await published_events.aclose()

But I get the following error:

RuntimeError: aclose(): asynchronous generator is already running

Is there a way to stop processing of an already running generator?

like image 890
Szabolcs Avatar asked Feb 14 '20 12:02

Szabolcs


Video Answer


1 Answers

It seems to be related to this issue. Noticable:

As shown in https://gist.github.com/1st1/d9860cbf6fe2e5d243e695809aea674c, it's an error to close a synchronous generator while it is being iterated.

...

In 3.8, calling "aclose()" can crash with a RuntimeError. It's no longer possible to reliably cancel a running asynchrounous generator.

Well, since we can't cancel running asynchrounous generator, let's try to cancel its running.

import asyncio
from contextlib import suppress


async def cancel_gen(agen):
    task = asyncio.create_task(agen.__anext__())
    task.cancel()
    with suppress(asyncio.CancelledError):
        await task
    await agen.aclose()  # probably a good idea, 
                         # but if you'll be getting errors, try to comment this line

...

if connection.is_disconnected():
    await cancel_gen(published_events)

Can't test if it'll work since you didn't provide reproducable example.

like image 179
Mikhail Gerasimov Avatar answered Oct 01 '22 03:10

Mikhail Gerasimov