How to find the longest sequence of letter in a string

Question

I want to find out the longest sequence of letter in a string

e.g. in the word Honorificabcdwert , the output will be abcd.

How can I do it?

My idea is to get the Ascii and then count the sequence until it breaks at some point. But I was able to proceed with only

DECLARE @t TABLE(ID INT IDENTITY,String VARCHAR(100))
INSERT INTO @t SELECT 'Honorificabcdwert'

;with Get_Individual_Chars_Cte AS
( 
   SELECT 
        ID
        ,Row_ID =ROW_NUMBER() Over(PARTITION by ID Order by ID) 
        ,SUBSTRING(String,Number,1) AS [Char]
        ,ASCII(SUBSTRING(String,Number,1)) AS [Ascii Value]

FROM @t  
INNER JOIN master.dbo.spt_values ON
 Number BETWEEN 1 AND LEN(String)
 AND type='P'

)

Select * from Get_Individual_Chars_Cte 

After this I don't know what to do. Help needed for this or any other way of doing so.

Answer 1

Will this help

DECLARE @t TABLE(ID INT IDENTITY,String VARCHAR(100))
INSERT INTO @t 
SELECT 'Honorificabcdwert' UNION ALL
SELECT 'AbCdEfxy' UNION ALL
SELECT 'abc1234defg' UNION ALL
SELECT 'XYZABCPPCKLMIDBABC' UNION ALL
SELECT 'MNOP$%^&~()MNOPQRS;:'


SELECT ID, OriginalString,Sequence
FROM (SELECT ID, REPLACE(string,'%','') AS Sequence,OriginalString,
      ROW_NUMBER() OVER(PARTITION BY ID ORDER BY LEN(string) DESC, string) AS rn
      FROM (SELECT OriginalString = b.String, CASE WHEN b.String LIKE a.strings THEN a.strings ELSE NULL END AS string, 
            b.ID, ROW_NUMBER() OVER(PARTITION BY ID ORDER BY LEN(strings) DESC, strings) AS rn
            FROM (SELECT COALESCE('%' + b.strings+a.strings + '%','%' + a.strings + '%') AS strings
                  FROM (SELECT SUBSTRING('ABCDEFGHIJKLMNOPQRSTUVWXYZ',t1.N,t2.N-t1.N+1) AS strings, t1.N
                        FROM (VALUES(1),(2),(3),(4),(5),(6),(7),(8),
                                    (9),(10),(11),(12),(13),(14),(15),
                                    (16),(17),(18),(19),(20),(21),(22),
                                    (23),(24),(25),(26)) t1(N)
                        CROSS JOIN (VALUES(1),(2),(3),(4),(5),(6),(7),(8),
                                          (9),(10),(11),(12),(13),(14),(15),
                                          (16),(17),(18),(19),(20),(21),(22),
                                          (23),(24),(25),(26)) t2(N)
                        WHERE t1.N <= t2.N) a
                  LEFT OUTER JOIN (SELECT REVERSE(SUBSTRING('ZYXWVUTSRQPONMLKJIHGFEDCBA',1,N)) AS strings, 1 AS ID
                                   FROM (VALUES(1),(2),(3),(4),(5),(6),(7),(8),
                                               (9),(10),(11),(12),(13),(14),(15),
                                               (16),(17),(18),(19),(20),(21),(22),
                                               (23),(24),(25),(26)) t1(N)
                                   UNION ALL SELECT '', 1) b ON a.N = b.ID) a
            CROSS JOIN @t b) a ) a
WHERE a.rn = 1
ORDER BY a.ID

Result

ID  OriginalString          Sequence
1   Honorificabcdwert       ABCD
2   AbCdEfxy                ABCDEF
3   abc1234defg             DEFG
4   XYZABCPPCKLMIDBABC      XYZABC
5   MNOP$%^&~()MNOPQRS;:    MNOPQRS

Based on your inputs provided in the course of discussion with @Martin Smith, the program is being developed. Please test it and let me know if it satisfies your requirement.