A CAM file is a CAM (computer-aided manufacturing) data file saved in the FastCAM format. It contains CAD (computer-aided design) information, which includes the processing path and material, thickness, and quantity details of the object. CAM files are similar to . DXF files developed by Autodesk.
Path.GetExtension
string myFilePath = @"C:\MyFile.txt";
string ext = Path.GetExtension(myFilePath);
// ext would be ".txt"
You may simply read the stream of a file
using (var target = new MemoryStream())
{
postedFile.InputStream.CopyTo(target);
var array = target.ToArray();
}
First 5/6 indexes will tell you the file type. In case of FLV its 70, 76, 86, 1, 5.
private static readonly byte[] FLV = { 70, 76, 86, 1, 5};
bool isAllowed = array.Take(5).SequenceEqual(FLV);
if isAllowed
equals true
then its FLV.
OR
Read the content of a file
var contentArray = target.GetBuffer();
var content = Encoding.ASCII.GetString(contentArray);
First two/three letters will tell you the file type.
In case of FLV its "FLV......"
content.StartsWith("FLV")
At the server you can check the MIME type, lookup flv mime type here or on google.
You should be checking that the mime type is
video/x-flv
If you were using a FileUpload in C# for instance, you could do
FileUpload.PostedFile.ContentType == "video/x-flv"
I'm not sure if this is what you want but:
Directory.GetFiles(@"c:\mydir", "*.flv");
Or:
Path.GetExtension(@"c:\test.flv")
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