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Is there a standard function in PHP that will find the day number of the year based on the current date?
Examples:
Jan 22nd = 22 Feb 27th = 58 Mar 5th = 64 If there isn't a standard function, has anyone built anything similar that would handle the conversion? What all is involved?
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You can simply use the PHP date() function to get the current data and time in various format, for example, date('d-m-y h:i:s') , date('d/m/y H:i:s') , and so on.
The date function in PHP is used to format the timestamp into a human desired format. The timestamp is the number of seconds between the current time and 1st January, 1970 00:00:00 GMT. It is also known as the UNIX timestamp.
php /*print date in dd/mm/yy format*/ print "Current date in dd/mm/yy format: " . date("d/m/y"); print "</br>"; /*print date in dd/mm/yyyy format*/ print "Current date in dd/mm/yyyy format: " . date("d/m/Y"); print "</br>"; /*print date in dd MON yyyy format*/ print "Current date in dd MON yyyy format: " .
date('z') + 1;
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