How to find Tablet or Phone in Android , Programmatically?

Question

My case is that the logic is same for both Phone and Tablet. But there is slight difference in the layout. And I tried with the following code

public static boolean findoutDeviceType(Context context)      {         return (context.getResources().getConfiguration().screenLayout &                         Configuration.SCREENLAYOUT_SIZE_MASK)>=                             Configuration.SCREENLAYOUT_SIZE_LARGE;     } 

Samsung Tab 10" has the resolution of 1280 * 800 and S3 has the resolution of 1270 * 720. And this code returns the Size as XLarge for both the Tab and Phone as its criteria for checking is > 960 * 720.

I have tested inserting the respective UI in the layout folder in Res as Layout, Layout-Large and Layout-xLarge . But this didn't effect in anyway. while checking it took the UI from the Layout folder.

Anyway even though I place the UI in the different layout folders, I have to check them in the class file to set the respective ContentView.

Is there any other way to find it?

Answer 1

This subject is discussed in the Android Training:

http://developer.android.com/training/multiscreen/screensizes.html#TaskUseSWQuali

Here is implementation,

Credit goes to ol_v_er for this simple and easy approach.

Some additional Information

You have now flag indicate whether your application is running on phone or tablet.

I have created two packages to handle UI and it's functionality,

com.phone com.tablet 

And you redirect control to your needed package

boolean tabletSize = getResources().getBoolean(R.bool.isTablet); if (tabletSize) {     // do something     //Start activity for tablet } else {     // do something else     //Start activity for phone      } 

Refer

Note :I think for both 10 inch and 7 inch screen app take resources from res/values-sw600dp/ . But To be more specific I think for 10 inch tablet screen we can use res/values-sw720dp/

<resources>     <bool name="isTablet">true</bool> </resources>