how to find partition of record oracle

Question

I have a table and there is a partition on it.

There are 16 hash partition which is starting from SUBSCRIBER_01 .. etc

Table name: SUBSCRIBER

Partition Column: CUSTOMER_ID (VARCHAR2 10)

Database : 11g

How can I find partition of a record?

Like Customer_ID=933587

Answer 1

Select the rowid for the row, and the DBMS_RowID.RowID_Object() procedure will extract the data object id.

http://docs.oracle.com/cd/B19306_01/appdev.102/b14258/d_rowid.htm#i997153

Look up that data object id in the data dictionary and read the subobject_name.

For example:

   SELECT dbms_rowid.rowid_object(ROWID) data_object_id
   FROM INVOICE
   WHERE INVOICE_ID = 2268041139:

   -- data_object_id = 546512

   select * from user_objects where data_object_id = 546512;

   -- SUBOBJECT_NAME = 'PART_P2099_P00'     
   -- OBJECT_TYPE = TABLE PARTITION
   -- OBJECT_ID = 464826
   -- DATA_OBJECT_ID = 546512

Answer 2

You can using this script:

SELECT L.*, O.SUBOBJECT_NAME
FROM 
  (
    SELECT DBMS_ROWID.ROWID_OBJECT(ROWID) DATA_OBJECT_ID, L.*
    FROM YOUR_TABLE L
    --WHERE L.ID = 123
  ) L
  JOIN 
  (
    SELECT SUBOBJECT_NAME, DATA_OBJECT_ID 
    FROM USER_OBJECTS
  ) O ON O.DATA_OBJECT_ID = L.DATA_OBJECT_ID
;