How to find multiple max value items in a list [duplicate]

Question

I'm trying to figure out how I can take a list of integers and return all the items in that list into another list as their max value, but with their index.

So I need to be able to do this without using enumeration, lambda, numpy, or anything of that sort. It has to be really basic methods for lists. Basically, things like append, max, etc. . . If for statements are fine too.

To clarify what I'm trying to do, say I have a list: [4, 34, 0, 0, 6, 34, 1] I want it to return [1, 5]

Answer 1

Simplest approach:

in [24]: a = [4, 34, 0, 0, 6, 34, 1]

In [25]: j=0

In [26]: M=[]

In [27]: m = max(a)

In [28]: for i in a:
    if i==m:
        M.append(j)
    j+=1
   ....:     

In [29]: M
Out[29]: [1, 5]

Using list-comprehension and enumerate, the above can be shortened to:

In [30]: [i for i, x in enumerate(a) if x == max(a)]
Out[30]: [1, 5]

Answer 2

A "fully manual" approach, using none of those pesky standard library functions:

def get_max_indices(vals):
    maxval = None
    index = 0
    indices = []
    while True:
        try:
            val = vals[index]
        except IndexError:
            return indices
        else:
            if maxval is None or val > maxval:
                indices = [index]
                maxval = val
            elif val == maxval:
                indices.append(index)
            index = index + 1

What it loses in brevity, it gains in... not much.