How to find max value in pair RDD?

Question

I have a spark pair RDD (key, count) as below

Array[(String, Int)] = Array((a,1), (b,2), (c,1), (d,3))

How to find the key with highest count using spark scala API?

EDIT: datatype of pair RDD is org.apache.spark.rdd.RDD[(String, Int)]

Answer 1

Use Array.maxBy method:

val a = Array(("a",1), ("b",2), ("c",1), ("d",3))
val maxKey = a.maxBy(_._2)
// maxKey: (String, Int) = (d,3)

or RDD.max:

val maxKey2 = rdd.max()(new Ordering[Tuple2[String, Int]]() {
  override def compare(x: (String, Int), y: (String, Int)): Int = 
      Ordering[Int].compare(x._2, y._2)
})

Answer 2

Use takeOrdered(1)(Ordering[Int].reverse.on(_._2)):

val a = Array(("a",1), ("b",2), ("c",1), ("d",3))
val rdd = sc.parallelize(a)
val maxKey = rdd.takeOrdered(1)(Ordering[Int].reverse.on(_._2))
// maxKey: Array[(String, Int)] = Array((d,3))

Quoting the note from RDD.takeOrdered:

This method should only be used if the resulting array is expected to be small, as all the data is loaded into the driver's memory.