How to find indices of first two elements in a list that are any of the elements in another list?

Question

How do I find the indices of the first two elements in a list that are any of the elements in another list?

For example:

story = ['a', 'b', 'c', 'd', 'b', 'c', 'c']
elementsToCheck = ['a', 'c', 'f', 'h']

In this case, the desired output is a list indices = [0,2] for strings 'a' and 'c'.

Answer 1

story = ['a', 'b', 'c', 'd', 'b', 'c', 'c']
elementsToCheck = ['a', 'c', 'f', 'h']

out = []
for i, v in enumerate(story):
    if v in elementsToCheck:
        out.append(i)
    if len(out) == 2:
        break

print(out)

Prints:

[0, 2]

Answer 2

Possibly the shortest way to implement this:

[i for i, x in enumerate(story) if x in elementsToCheck][:2]