How to find index of STRING array in Java from a given value?

Question

Type in:

Arrays.asList(TYPES).indexOf("Sedan");

String carName = // insert code here
int index = -1;
for (int i=0;i<TYPES.length;i++) {
    if (TYPES[i].equals(carName)) {
        index = i;
        break;
    }
}

After this index is the array index of your car, or -1 if it doesn't exist.

for (int i = 0; i < Types.length; i++) {
    if(TYPES[i].equals(userString)){
        return i;
    }
}
return -1;//not found

You can do this too:

return Arrays.asList(Types).indexOf(userSTring);

I had an array of all English words. My array has unique items. But using…

Arrays.asList(TYPES).indexOf(myString);

…always gave me indexOutOfBoundException.

So, I tried:

Arrays.asList(TYPES).lastIndexOf(myString);

And, it worked. If your arrays don't have same item twice, you can use:

Arrays.asList(TYPES).lastIndexOf(myString);

Use Arrays class to do this

Arrays.sort(TYPES);
int index = Arrays.binarySearch(TYPES, "Sedan");

try this instead

org.apache.commons.lang.ArrayUtils.indexOf(array, value);

No built-in method. But you can implement one easily:

public static int getIndexOf(String[] strings, String item) {
    for (int i = 0; i < strings.length; i++) {
        if (item.equals(strings[i])) return i;
    }
    return -1;
}