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I have two lists that have the same vectors but with different length
list1 <- list(a = 1:10, b = 3:20)
list2 <- list(a = c(2,5,8), b = c(3,5,11,20))
I would like to find elements from each vector in list1 that are not present in the corresponding vector in list2. There are similar questions answered for other scripts instead of R.
I expect the final list is
lst <- list(a=c(1,3,4,6,7,9,10),b=c(4,6:10,12:19))
Thank you for help.
857
If we want all the elements of a vector that are not in another vector then we can use setdiff () method in R. It takes two vectors and returns a new vector with the elements of the first vector that are not present in the second vector.
Write a R program to find all elements of a given list that are not in another given list. l1 = list("x", "y", "z") l2 = list("X", "Y", "Z", "x", "y", "z") print("Original lists:") print( l1) print( l2) print("All elements of l2 that are not in l1:") setdiff ( l2, l1)
How to find items in one list that are not in another list in C#? The Except () method requires two collections and find those elements which are not present in second collection Except extension method doesn't return the correct result for the collection of complex types.
Let’s dive right in! The previous output of the RStudio console shows that our example data is a list with four list elements. In this section, I’ll show how to identify the index positions of all list elements that contain a particular value.
We can use
mapply(setdiff,list1,list2)
#$a
#[1] 1 3 4 6 7 9 10
#$b
#[1] 4 6 7 8 9 10 12 13 14 15 16 17 18 19
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