How to find Column with same (some x value) value repeated more than once? Needs to return those rows.

Question

There is a table called contacts with columns id, name, address, ph_no etc.
I need to find out rows with the same name, if the rows count is more than 1, show those rows.

For example:
Table: contacts

id--------name--------address---------ph_no--------
111       apple       U.K             99*******
112       banana      U.S             99*******
123       grape       INDIA           99*******
143       orange      S.AFRICA        99*******
152       grape       KENYA           99*******

For the above table I need to get rows with same column name data like the below:

id--------name--------address---------ph_no--------
123       grape       INDIA           99*******
152       grape       KENYA           99*******

I need to get the rows based on the name what I given as argument like below example syntax:

select * from contacts where name='grape' and it's count(*) >1 return those rows.

How can I achieve the solution for above problem.

Answer 1

As @vc74 suggests analytic functions would work work a lot better here; especially if your data has any volume.

select id, name, address, ph_no ...
  from ( select c.*, count(name) over ( partition by name ) as name_ct
           from contacts c )
 where name_ct > 1
       ;

EDIT

restricting on specific names the table contacts should really have an index on name and the query would look like this:

select id, name, address, ph_no ...
  from ( select c.*, count(name) over ( partition by name ) as name_ct
           from contacts c
          where name = 'grape' )
 where name_ct > 1
       ;