I am totally new to regular expressions. And what I need to achieve is, I have a string variable containing the following string for example,
"My Name is #P_NAME# and I am #P_AGE# years old"
I need to extract the two strings P_NAME and P_AGE using regular expressions (to a string array or two string variables etc). i.e. the string starts with a # and ends with a # and I need to extract the middle part.
How can I do this in C# using Regular Expressions..?
And how can I extract the same above in case I have a new line character in between as well. i.e. for example,
"My Name is #P_NAME# and \r\n I am #P_AGE# years old".
Thanks
Thanks Everyone...
Following worked for me... I cannot publish my own answer as the answer until 8 hours expires in stackoverflow... :)
string str = "My Name is #P_NAME# and \r\n I am #P_AGE# years old";
MatchCollection allMatchResults = null;
var regexObj = new Regex(@"#\w*#");
allMatchResults = regexObj.Matches(str);
'allMatchResults' contains #P_NAME# and #P_AGE# (i.e. including # character). But having it helps my other logics than not having it.
You can do it like this
using System.Text.RegularExpressions;
using System;
public class Test
{
public static void Main(){
string s = "My name is #Dave# and I am #18# years old";
Regex r = new Regex(@"#(.+?)#");
MatchCollection mc = r.Matches(s);
Console.WriteLine("Name is " + mc[0].Groups[1].Value);
Console.WriteLine("Age is " + mc[1].Groups[1].Value);
}
}
Demo here
I don't know what your application is but I must say this is not a very robust looking data transfer method. Start getting a few extra #s in there and it all goes wrong. For example people with # in their names!
However if you can guarantee that you will always be working with a string of this format then this does work.
Explanation of Regex #(.+?)#
First # matches a #
( begins a group. Indexed into in .Groups[1] in the code. [0] is the whole match eg #Dave# not just Dave
.+? matches at least one character. . is a character. + is repetition (at least
once). And ? tells the regex engine to be lazy - so don't match a # as that will get matched by our final #
) close the group
# matches another # - the 'closing' one in this case
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