How to extract a filename from a URL & append a word to it?

Question

I have the following url:

url = http://photographs.500px.com/kyle/09-09-201315-47-571378756077.jpg

I would like to extract the file name in this url: 09-09-201315-47-571378756077.jpg

Once I get this file name, I'm going to save it with this name to the Desktop.

filename = **extracted file name from the url**      download_photo = urllib.urlretrieve(url, "/home/ubuntu/Desktop/%s.jpg" % (filename)) 

After this, I'm going to resize the photo, once that is done, I've going to save the resized version and append the word "_small" to the end of the filename.

downloadedphoto = Image.open("/home/ubuntu/Desktop/%s.jpg" % (filename))                resize_downloadedphoto = downloadedphoto.resize.((300, 300), Image.ANTIALIAS) resize_downloadedphoto.save("/home/ubuntu/Desktop/%s.jpg" % (filename + _small)) 

From this, what I am trying to achieve is to get two files, the original photo with the original name, then the resized photo with the modified name. Like so:

09-09-201315-47-571378756077.jpg

09-09-201315-47-571378756077_small.jpg

How can I go about doing this?

Answer 1

You can use urllib.parse.urlparse with os.path.basename:

import os from urllib.parse import urlparse  url = "http://photographs.500px.com/kyle/09-09-201315-47-571378756077.jpg" a = urlparse(url) print(a.path)                    # Output: /kyle/09-09-201315-47-571378756077.jpg print(os.path.basename(a.path))  # Output: 09-09-201315-47-571378756077.jpg 

Answer 2

os.path.basename(url)

Why try harder?

In [1]: os.path.basename("https://example.com/file.html") Out[1]: 'file.html'  In [2]: os.path.basename("https://example.com/file") Out[2]: 'file'  In [3]: os.path.basename("https://example.com/") Out[3]: ''  In [4]: os.path.basename("https://example.com") Out[4]: 'example.com' 

Note 2020-12-20

Nobody has thus far provided a complete solution.

A URL can contain a ?[query-string] and/or a #[fragment Identifier] (but only in that order: ref)

In [1]: from os import path  In [2]: def get_filename(url):    ...:     fragment_removed = url.split("#")[0]  # keep to left of first #    ...:     query_string_removed = fragment_removed.split("?")[0]    ...:     scheme_removed = query_string_removed.split("://")[-1].split(":")[-1]    ...:     if scheme_removed.find("/") == -1:    ...:         return ""    ...:     return path.basename(scheme_removed)    ...:  In [3]: get_filename("a.com/b") Out[3]: 'b'  In [4]: get_filename("a.com/") Out[4]: ''  In [5]: get_filename("https://a.com/") Out[5]: ''  In [6]: get_filename("https://a.com/b") Out[6]: 'b'  In [7]: get_filename("https://a.com/b?c=d#e") Out[7]: 'b'