Is it possible to extend existing "standard" filters (date
, number
, lowercase
etc)?
In my case I need to parse date from YYYYMMDDhhmmss format so I'd like to extend (or override) date
filter instead of writing my own.
Using filters in view templates Filters can be applied to the result of another filter. This is called "chaining" and uses the following syntax: {{ expression | filter1 | filter2 | ... }} E.g. the markup {{ 1234 | number:2 }} formats the number 1234 with 2 decimal points using the number filter.
Extends the destination object dst by copying own enumerable properties from the src object(s) to dst . You can specify multiple src objects. If you want to preserve original objects, you can do so by passing an empty object as the target: var object = angular. extend({}, object1, object2) .
I prefer to implement the decorator pattern, which is very easy in AngularJS.
If we take @pkozlowski.opensource example, we can change it to something like:
myApp.config(['$provide', function($provide) {
$provide.decorator('dateFilter', ['$delegate', function($delegate) {
var srcFilter = $delegate;
var extendsFilter = function() {
var res = srcFilter.apply(this, arguments);
return arguments[2] ? res + arguments[2] : res;
}
return extendsFilter;
}])
}])
And then in your views, you can use both.. the standard output and the extended behavior.
with the same filter
<p>Standard output : {{ now | date:'yyyyMMddhhmmss' }}</p>
<p>External behavior : {{ now | date:'yyyyMMddhhmmss': ' My suffix' }}</p>
Here is a working fiddle illustrating both techniques: http://jsfiddle.net/ar8m/9dg0hLho/
I'm not sure if I understand your question correctly, but if you would like to extend functionality of existing filters you could create a new filter that decorates an existing one. Example:
myApp.filter('customDate', function($filter) {
var standardDateFilterFn = $filter('date');
return function(dateToFormat) {
return 'prefix ' + standardDateFilterFn(dateToFormat, 'yyyyMMddhhmmss');
};
});
and then, in your template:
{{now | customDate}}
Having said the above, if you simply want to format a date according to a given format this can be done with the existing date filter:
{{now | date:'yyyyMMddhhmmss'}}
Here is the working jsFiddle illustrating both techniques: http://jsfiddle.net/pkozlowski_opensource/zVdJd/2/
Please note that if a format is not specified AngularJS will assume that this is 'medium' format (the exact format depends on a locale). Check http://docs.angularjs.org/api/ng.filter:date for more.
The last remark: I'm a bit confused about the 'parse from' part of your question. The thing is that filters are used to parse an object (date in this case) to string and not vice verse. If you are after parsing strings (from an input) representing dates you would have to look into NgModelController#$parsers (check the "Custom Validation" part in http://docs.angularjs.org/guide/forms).
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