How to escape the bang (!) character in Linux bash shell?

Question

I cannot for the life of me figure out how to escape the ! character in Bash. For example, I want to print this:

Text text text!

I've tried this:

echo "Text text text\!" 

but that prints this instead:

Text text text\!

(with an extra backslash).

How can I do this?

Answer 1

Try this:

 echo 'Text text text!' 

or

 echo "Text text text"'!' 

or

 echo -e "Text text text\x21" 

Answer 2

Single quote:

echo 'Text Text Text!' 

That does it for me.