OK, this is kind of funny. Here is the XML:
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
<parent>
<groupId>com.parent</groupId>
<artifactId>parent</artifactId>
<version>1.0-SNAPSHOT</version>
<relativePath>../pom.xml</relativePath>
</parent>
<build>
<sourceDirectory>src</sourceDirectory>
</build>
I want to use the simple BeautifulSoup hierarchical notation to get to the node actually named <parent> but parent is actually a reserved attribute label in this API.
with open(pom) as pomHandle:
soup = BeautifulSoup(pomHandle)
#this returns the proper build node
buildNode = soup.project.build
#this does not return the proper parent node but the XML parent of the project node
#(which is the whole doc) because 'parent' is reserved
parentNode = soup.project.parent
How do I override this limitation?
You can use find() instead:
soup.project.find('parent')
Essentially this is the same thing since BeautifulSoup uses find under-the-hood in __getattr__() method of a Tag class.
Hope that helps.
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