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I do a full text search using LIKE clause and the text can contain a '%'.
What is a good way to search for a % sign in an sqlite database?
I did try
SELECT * FROM table WHERE text_string LIKE '%[%]%'
but that doesn't work in sqlite.
545
Double-quotes in SQLite identifiers are escaped as two double quotes. SQLite identifiers preserve case, but they are case-insensitive towards ASCII letters. It is possible to enable unicode-aware case-insensitivity.
In ANSI SQL, the backslash character (\) is the escape character. To search for data that begins with the string \abc , the WHERE clause must use an escape character as follows: ... where col1 = '\\abc';
Description. The SQLite || operator allows you to concatenate 2 or more strings together.
Escape sequences are used within an SQL statement to tell the driver that the escaped part of the SQL string should be handled differently. When the JDBC driver processes the escaped part of an SQL string, it translates that part of the string into SQL code that SQL Server understands.
From the SQLite documentation
If the optional ESCAPE clause is present, then the expression following the ESCAPE keyword must evaluate to a string consisting of a single character. This character may be used in the LIKE pattern to include literal percent or underscore characters. The escape character followed by a percent symbol (%), underscore (_), or a second instance of the escape character itself matches a literal percent symbol, underscore, or a single escape character, respectively.
95
We can achieve same thing with the below query
SELECT * FROM table WHERE instr(text_string, ?)>0
Here :
? => your search word
Example :
You can give text directly like
SELECT * FROM table WHERE instr(text_string, '%')>0
SELECT * FROM table WHERE instr(text_string, '98.9%')>0 etc.
Hope this helps better.
3
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